If the value of n(n²-1) is six time value of ∑d² then what is the value of r??​

If the value of n(n²-1) is six time value of ∑d² then what is the value of r??​

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  1. Given : the value of n(n²-1) is six time value of ∑d²

    To Find : the value of r

    Solution:

    rank correlation coefficient r = 1 – 6 ∑ (di)² / (n(n² – 1))

    n = numbers

    ∑ (di)² = sum of squares of the differences in ranks

    r = rank correlation coefficient

    Now its given that n(n²-1) is six time value of ∑d²

    => n(n²-1) = 6 ∑d²

    Substituting value in formula

    r = 1 – 6 ∑ (di)² / (n(n² – 1))

    => r = 1 – 6 ∑ (di)² / 6 ∑d²

    => r = 1 – 1

    => r = 0

    value of r is 0

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