if the sum of the zeros of the polynomial 2xsquare _3kxsquare+4x_5 is 6 find the value k​

2 thoughts on “if the sum of the zeros of the polynomial 2xsquare _3kxsquare+4x_5 is 6 find the value k​”

1. Step-by-step explanation:

   p(x) = 2x²-3kx² + 4x – 5

   [tex]sum \: \alpha + \beta + \gamma = \frac{ – b}{a} [/tex]

   [tex] \alpha + \beta + \gamma = 6 \\ 6 = \frac{ – 4}{2 – 3k } \\ 6(2 – 3k) = – 4 \\ 12 + 4 = 18k \\ \frac{16}{18 } = k \\ \frac{8}{ 9 } = k[/tex]

   pls check the question and choose the correct ans

   k= 4

   or k= 8/9

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2. Answer :

   k = 8/9

   Explanation :

   Given polynomial,

   ⇒ 2x² – 3kx² + 4x – 5

   On comparing with ax² + bx + c we get,

   • a = (2 – 3k)
   • b = 4
   • c = -5

   Where, the sum of the zeros given is 6

   Find the value of ‘k’

   Let’s the zeros be α, and β

   Then,

   ⇒ α + β = -b/a

   Substitute the given values,

   ⇒ 6 = -4/(2 – 3k)

   ⇒ 6(2 – 3k) = -4

   ⇒ 12 – 18k = -4

   ⇒ 12 + 4 = 18k

   ⇒ 16 = 18k

   ⇒ 16/18 = k

   ⇒ 8/9

   ∴ The value of ‘k’ is 8/9.

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