if the sum of the zeroes of the quadratic polynomial 3×2 – kx + 6 is 3, then find the value of k. About the author Anna
Answer: We have :3×2-Kx+6 is 3 3(3)2-K(3)+6 3 (9)- 3k +6=0 27-3k+6=0 33-3k =0 -3k =33 k =33÷(-3) k=-11 Reply
Answer:
We have :3×2-Kx+6 is 3
3(3)2-K(3)+6
3 (9)- 3k +6=0
27-3k+6=0
33-3k =0
-3k =33
k =33÷(-3)
k=-11