If the sum of first n terms of an AP is 3n2-5, then the third term is
a. 30 b.-15 c. -30 d.15
ii. If a,b,c are in AP then b =——–
a.
−
2
b. −
2
c.
+
2
d. +
2
iii. Find the 6th term from the end of the AP: 17, 14, 11……..-40
a. -25 b. -20 c. -15 d. 15
iv. In the following AP, find the missing terms: 5, ——-, ——-, 91
2
a.
13
2
, 8 1
2
b. 13
2
,
16
2
c.
16
2
,
13
2
d. 8 1
2
,
13
2
Answer:
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