if the sum of-8 and a is -3 ,then find the additive inverse of a step by step About the author Athena
Step-by-step explanation: For a number a , it’s multiplicative inverse b is such that a ⋅ b = 1 which is the multiplicative identity. For a number a , it’s additive inverse c would be such that a + c = 0 where 0 is additive identity. Thus, for a = − 8 It’s additive inverse be c . Then − 8 + c = 0 Now, adding 8 to both sides, c = 8 . Let the multiplicative inverse be b . Then a ⋅ b = 1 ⇒ − 8 ⋅ b = 1 Multiplying both sides with − 1 8 b = − 1 8 Reply
Step-by-step explanation: -8+a= -3 if we subtract-8 and -3 we get -5 so…. -8+-5=-3 and when we do the value of a in additive inverse we get 5 so the final answer is -8+5=-3 hope this help you! Reply
Step-by-step explanation:
For a number
a
, it’s multiplicative inverse
b
is such that
a
⋅
b
=
1
which is the multiplicative identity.
For a number
a
, it’s additive inverse
c
would be such that
a
+
c
=
0
where
0
is additive identity.
Thus, for
a
=
−
8
It’s additive inverse be
c
.
Then
−
8
+
c
=
0
Now, adding
8
to both sides,
c
=
8
.
Let the multiplicative inverse be
b
.
Then
a
⋅
b
=
1
⇒
−
8
⋅
b
=
1
Multiplying both sides with
−
1
8
b
=
−
1
8
Step-by-step explanation:
-8+a= -3
if we subtract-8 and -3 we get -5
so….
-8+-5=-3
and when we do the value of a in additive inverse we get 5
so the final answer is
-8+5=-3
hope this help you!