if the roots of equations has real and equal than find value of m (m-12)x²+2(m-12)x+2=0 About the author Charlotte
Here a = (m-12), b = 2(m-12) and c = 2 ATQ : [tex] {b}^{2} – 4ac = 0 \\ \\ = > {(2(m – 12))}^{2} – 4 \times (m – 12) \times 2 = 0\\ \\ = > 4 ({m}^{2} – 24m + 144) – 8m + 96 = 0 \\ \\ = > 4 {m}^{2} – 96m + 576 – 8m + 96 = 0 \\ \\ = > 4 {m}^{2} – 104m + 672 = 0 \\ \\ = > {m}^{2} – 26m + 168 = 0 \\ \\ = > {m}^{2} – 14m – 12m + 168 = 0 \\ \\ = > m(m – 14) – 12(m – 14) = 0 \\ \\ = > (m – 14) (m- 12) = 0[/tex] Values of m = 14 and 12 ✔✔ __________________________ Hope it helps ☺ Fóllòw Më ❤ Reply
Answer: For real and equal roots, the Discriminant should be 0. So the value is either 12 or 14 for the required situation Reply
Here a = (m-12), b = 2(m-12) and c = 2
ATQ :
[tex] {b}^{2} – 4ac = 0 \\ \\ = > {(2(m – 12))}^{2} – 4 \times (m – 12) \times 2 = 0\\ \\ = > 4 ({m}^{2} – 24m + 144) – 8m + 96 = 0 \\ \\ = > 4 {m}^{2} – 96m + 576 – 8m + 96 = 0 \\ \\ = > 4 {m}^{2} – 104m + 672 = 0 \\ \\ = > {m}^{2} – 26m + 168 = 0 \\ \\ = > {m}^{2} – 14m – 12m + 168 = 0 \\ \\ = > m(m – 14) – 12(m – 14) = 0 \\ \\ = > (m – 14) (m- 12) = 0[/tex]
Values of m = 14 and 12 ✔✔
__________________________
Hope it helps ☺
Fóllòw Më ❤
Answer:
For real and equal roots, the Discriminant should be 0. So the value is either 12 or 14 for the required situation