if the roots of a quadratic equation are 4 and -5 form the quadratic equation About the author Vivian
Answer: x² – x – 20 Step-by-step explanation: We know form of Quadratic equation as x² – (å+ñ)x + åñ If å and ñ ane roots of the equation Given that å = 4 and ñ = -5 so Sum of roots is 4-5 = -1 And Product of roots is (4)(-5) = -20 So equation formed is x² + x -20 We can also find it in an another way. i.e. If 4 and -5 are roots of equation then (x-4) and (x+5) are factors of equation So equation formed will be p(x) = (x-4)(x+5) = x(x +5) – 4(x + 5) = x² + 5x – 4x – 20 = x² + x – 20 Reply
Answer: [tex] = {x}^{2} – (sum \: of \: zeroes)x + (product \: of \: zeroes) \\= {x}^{2} – (4 – 5)x + (4 \times – 5) \\= {x}^{2} + x – 20[/tex] Reply
Answer:
x² – x – 20
Step-by-step explanation:
We know form of Quadratic equation as
x² – (å+ñ)x + åñ If å and ñ ane roots of the equation
Given that å = 4 and ñ = -5
so Sum of roots is 4-5 = -1
And Product of roots is (4)(-5) = -20
So equation formed is
x² + x -20
We can also find it in an another way. i.e.
If 4 and -5 are roots of equation then
(x-4) and (x+5) are factors of equation
So equation formed will be
p(x) = (x-4)(x+5)
= x(x +5) – 4(x + 5)
= x² + 5x – 4x – 20
= x² + x – 20
Answer:
[tex] = {x}^{2} – (sum \: of \: zeroes)x + (product \: of \: zeroes) \\= {x}^{2} – (4 – 5)x + (4 \times – 5) \\= {x}^{2} + x – 20[/tex]