if the product of two roots of equation x³-3x+k=10 is -2 then find the value of k​

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1. Answer:

   if the product of two roots of equation x³-3x+k=10 is -2 then find the value of k

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2. Answer:

   [tex]x {}^{3} – 3x + k = 10 \\ (2) {}^{3} – 3(2) + k = 10 \\ 8 – 6 + k = 10 \\ 4 + k = 10 \\ k = 10 – 4 \\ k = 6[/tex]

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