if the principal is RS 1000 the rate of interest is 10% the duration is 6 yrs what would be the simple interest About the author Maria
Given: Principal = Rs. 1000 Rate = 10 % Time = 6 years What To Find: We have to find the simple interest. Formula Needed: [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex] Where, SI = Simple Interest P = Principal R = Rate T = Time Solution: Using the formula, [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex] Substitute the values, [tex]\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}[/tex] Cancel the zeros, [tex]\sf \implies SI = 10 \times 10 \times 6[/tex] Multiply the values, [tex]\sf \implies SI = Rs. \: 600[/tex] Final Answer: ∴ Thus, the SI of the follwing is Rs. 600. Reply
Given: Principal = Rs. 1000 Rate = 10 % Time = 6 years What To Find: We have to find the simple interest. Formula Needed: [tex]\it SI = \dfrac{P \times R \times T}{100}[/tex] Where, SI = Simple Interest P = Principal R = Rate T = Time Solution: Using the formula, [tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex] Substitute the values, [tex]\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}[/tex] Cancel the zeros, [tex]\sf \implies SI = 10 \times 10 \times 6[/tex] Multiply the values, [tex]\sf \implies SI = Rs. \: 600[/tex] Final Answer: ∴ Thus, the SI of the follwing is Rs. 600. Reply
Given:
What To Find:
We have to find the simple interest.
Formula Needed:
[tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]
Where,
Solution:
Using the formula,
[tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]
Substitute the values,
[tex]\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}[/tex]
Cancel the zeros,
[tex]\sf \implies SI = 10 \times 10 \times 6[/tex]
Multiply the values,
[tex]\sf \implies SI = Rs. \: 600[/tex]
Final Answer:
∴ Thus, the SI of the follwing is Rs. 600.
Given:
Principal = Rs. 1000
Rate = 10 %
Time = 6 years
What To Find:
We have to find the simple interest.
Formula Needed:
[tex]\it SI = \dfrac{P \times R \times T}{100}[/tex]
Where,
SI = Simple Interest
P = Principal
R = Rate
T = Time
Solution:
Using the formula,
[tex]\sf \implies SI = \dfrac{P \times R \times T}{100}[/tex]
Substitute the values,
[tex]\sf \implies SI = \dfrac{1000 \times 10 \times 6}{100}[/tex]
Cancel the zeros,
[tex]\sf \implies SI = 10 \times 10 \times 6[/tex]
Multiply the values,
[tex]\sf \implies SI = Rs. \: 600[/tex]
Final Answer:
∴ Thus, the SI of the follwing is Rs. 600.