.. If the points (x, y) is equidistant from (a,0)
and (2a, a) then show that x + y – 2a=0.​

1 thought on “.. If the points (x, y) is equidistant from (a,0)<br />and (2a, a) then show that x + y – 2a=0.​”

1. Step-by-step explanation:

   (x, y) is equidistant from (a,0) and (2a, a)

   => (a-x)²+(0-y)² = (2a-x)²+(a-y)²

   => a²-2ax+x²+y² = 4a²-2(2a)(x)+x²+a²-2ay+y²

   => -2ax = 4a²-4ax-2ay

   => 4a²-4ax-2ay+2ax = 0

   => 4a²-2ax-2ay = 0

   => 2a ( 2a-x-y) = 0

   => 2a-x-y = 0

   => -(2a-x-y) = -(0)

   => x+y-2a = 0 , which is the require equation

   Hence proved

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