Answer: Perimeter of rectangle = 2(l+b) 34= 2(x-1)+(x+4) 34\2=(x-1)+(x+4) 17= x+x-1+4 17=2x+3 17-3=2x 14=2x x=7 width=(x-1) =(7-1) =6 length =(x+4)= (7+4) =11 Reply
G I V E N : Given that, 34cm is the perimeter of a rectangle and (x-1)cm, (x+4) are the breadth and length of the rectangle respectively. T O F I N D : We have to find the value of x. S O L U T I O N : We know that, Perimeter of the rectangle = 2(Length+Breadth) Here, Perimeter of the rectangle = 34cm Length of the rectangle = (x+4)cm Breadth of the rectangle = (x-1)cm Now, substituting the values : 34cm = 2[ (x+4) + (x-1) ] 34cm = 2[ x + 4 + x – 1 ] 34cm = 2[ 2x + 3 ] 34cm = 4x + 6 34cm – 6 = 4x 28cm = 4x 28cm/4 = x x = 7cm Therefore, x = 7cm Length = (x+4) = 11cm Breadth = (x-1) = 6cm V E R I F I C A T I O N : Now, let’s substitute these values and check whether it’s correct or not : Perimeter of rectangle = 2(Length + Breadth) 34cm = 2(11cm + 6cm) 34cm = 2(17cm) 34cm = 34cm LHS = RHS Hence, verified! Reply
Answer:
Perimeter of rectangle = 2(l+b)
34= 2(x-1)+(x+4)
34\2=(x-1)+(x+4)
17= x+x-1+4
17=2x+3
17-3=2x
14=2x
x=7
width=(x-1) =(7-1)
=6
length =(x+4)= (7+4)
=11
G I V E N :
Given that, 34cm is the perimeter of a rectangle and (x-1)cm, (x+4) are the breadth and length of the rectangle respectively.
T O F I N D :
We have to find the value of x.
S O L U T I O N :
We know that,
Here,
Now, substituting the values :
Therefore,
V E R I F I C A T I O N :
Now, let’s substitute these values and check whether it’s correct or not :
Hence, verified!