If the number 2345a 60b is exactly divisible by 3 and 5, then find the maximum value of a+b is About the author Aubrey
Answer: 16 Step-by-step explanation: We know, If the sum of digits of a number is divisible by 3 then the number is divisible by 3 So, 2+3+4+5+(7) = 21 6+0+9 = 15 Reply
Answer:
16
Step-by-step explanation:
We know,
If the sum of digits of a number is divisible by 3 then the number is divisible by 3
So,
2+3+4+5+(7) = 21
6+0+9 = 15
Answer:
Khdlliyslushd
Step-by-step explanation:
Jr kya khsjskhdlhoiddkhddpyuelgfljdek