If the nth term of an A.P. is(3n + 1). then thesum of its first ‘n terms isA2n2 +4n33n2 +4nBC3n2 +5n2D3n2+4n2 About the author Autumn
Step-by-step explanation: Tn=Sn−Sn−1 .(1) Now Sn=3n2+4n ∴Sn−1=3(n−1)2+4(n−1)=3n2−2n−1 ∴Tn=(3n2−4n)−(3n2−2n−1), by (1) =6n+1 ∴T1=7,T2=13,T3=19,______ ∴a=7,d=6. Reply
Step-by-step explanation:
Tn=Sn−Sn−1 .(1)
Now Sn=3n2+4n
∴Sn−1=3(n−1)2+4(n−1)=3n2−2n−1
∴Tn=(3n2−4n)−(3n2−2n−1), by (1)
=6n+1
∴T1=7,T2=13,T3=19,______
∴a=7,d=6.