if the multiplicative inverse of minus 2 by 5 is added to the additive inverse of minus 3 whole 1 by 2 what is sum obtained​

2 thoughts on “if the multiplicative inverse of minus 2 by 5 is added to the additive inverse of minus 3 whole 1 by 2 what is sum obtained​”

1. Answer:

   Step-by-step explanation:

   3 1/3 ÷ 5/3 – 1/10 of 2 ½ + 7/4

   = (3 × 3 + 1)/3 ÷ 5/3 – 1/10 of (2 × 2 + 1)/2 + 7/4

   = 10/3 ÷ 5/3 – 1/10 of 5/2 + 7/4

   [‘of’ simplified]

   = 10/3 × 3/5 – ½ × ½ + 7/4 [‘÷’ simplified]

   = 2/1 – ¼ + 7/4 [‘×’ simplified]

   = (2 × 4)/1 × 4) – (1 × 1)/4 × 1) + (7 × 1)/4 × 1)

   = 8/4 – ¼ + 7/4

   [Now the denominators are same of all the fractions]

   = (8 – 1 + 7)/4 [‘+’ and ‘-‘ simplified]

   = 14/4

   = 7/2

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2. Answer:

   34 is your answer hope it helps you

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