If the HCF of 210 and 55 is expressible in the form of 210×5×55×A ,then find the value of (2-A)​

2 thoughts on “If the HCF of 210 and 55 is expressible in the form of 210×5×55×A ,then find the value of (2-A)​”

1. Answer:

   Thus 2-A=2-(-19)=21

   Step-by-step explanation:

   First applying division lemma on 210 and 55

   210=3*55+45

   Now applying division lemma on 55 and 45

   55=45*1+10

   Now applying division lemma on 45 and 10

   45=10*4+5

   Now applying division lemma on 10 and 5

   10=2*5+0

   Here remainder is zero

   So HCF(210,55)=5

   Given that

   HCF=210*5+55*A

   5=210*5+55A

   55A=5-1050=-1045

   A=-1045/5=-19

   Thus 2-A=2-(-19)=21

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2. Answer:

   y=19

   Step-by-step explanation:

   Since now the remainder is zero, therefore divisor at this stage, that is 5, is the HCF of 210 and 55. Comparing equation (vi) with the given equation: 5=210×5+55y, we get, y=−19. This is the required solution.

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