if the HCF and the LCM of two positive integers a and b X and Y respectively then x² y² by a²b² is equal to​

1 thought on “if the HCF and the LCM of two positive integers a and b X and Y respectively then x² y² by a²b² is equal to​”

1. Answer:

   1

   Step-by-step explanation:

   lcm × hcf = product of two numbers

   ab= xy

   a²b² = x²y²

   x²y²/a²b² = 1

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