if the distance between point a(2,2)and b(-1,4) equal to 5 what is the value of x About the author Maria
Answer: We have, P=(2,2),Q=(5,x) and PQ=5 We know that d 2 =(x 2 −x 1 ) 2 +(y 2 −y 1 ) 2 Therefore, PQ 2 =(5−2) 2 +(x−2) 2 5 2 =(3) 2 +(x−2) 2 25=9+(x−2) 2 (x−2) 2 =16 x−2=±4 x=6 or x=−2 Hence, this is the answer. Reply
Answer:
We have,
P=(2,2),Q=(5,x) and PQ=5
We know that
d
2
=(x
2
−x
1
)
2
+(y
2
−y
1
)
2
Therefore,
PQ
2
=(5−2)
2
+(x−2)
2
5
2
=(3)
2
+(x−2)
2
25=9+(x−2)
2
(x−2)
2
=16
x−2=±4
x=6 or x=−2
Hence, this is the answer.