If the area of a triangle is 1176 cm² and base : corresponding altitude is 3:4, then the altitudeof the triangle is:1) 42 cm2) 52 cm3) 54 cm4) 56cm About the author Charlie
Answer: Given :– Area of triangle = 1176 cm² Ratio of base to altitude = 3:4 To Find :– Altitude Solution :– Let the base be 3x and altitude be 4x [tex] \sf \: 1176 = \dfrac{1}{2} \times 3x \times 4x[/tex] [tex] \sf \: 1176 \times 2 = 3x \times 4x[/tex] [tex] \sf \: 2352 = 12 {x}^{2} [/tex] [tex] \sf \dfrac{2352}{12} = {x}^{2} [/tex] [tex] \sf \:196 = {x}^{2} [/tex] [tex] \sf \: \sqrt{196} = \sqrt{ {x}^{2} } [/tex] [tex] \sf \: 14 = x[/tex] Altitude = 4x [tex] \sf \: 4 x[/tex] [tex] \sf \: 4(14)[/tex] [tex] \sf \: 56[/tex] Option 4 Reply
[tex] \huge { \blue { \fbox{ \red{Qᴜᴇꜱᴛɪᴏɴ}}}}[/tex] If the area of a triangle is 1176 cm² and base : corresponding altitude is 3:4, then the altitude of the triangle is: 1) 42 cm 2) 52 cm 3) 54 cm 4) 56cm [tex] \huge { \blue{\fbox{ \red{ᴀnswer}}}}[/tex] ɢɪᴠᴇɴ: ᴀʀᴇᴀ ᴏꜰ ᴛʀɪᴀɴɢʟᴇ = 1176 ᴄᴍᒾ ʀᴀᴛɪᴏ ᴏꜰ ʙᴀꜱᴇ ᴛᴏ ᴀʟᴛɪᴛᴜᴅᴇ = 3:4 ᴛᴏ ꜰɪɴᴅ: ᴀʟᴛɪᴛᴜᴅᴇ ꜱᴏʟᴜᴛɪᴏɴ: ʟᴇᴛ ᴛʜᴇ ʙᴀꜱᴇ ʙᴇ ‘3x’ ᴀɴᴅ ᴀʟᴛɪᴛᴜᴅᴇ ʙᴇ ‘4x’ [tex] \red\rightarrow1176 = \frac{1}{2} \times 3x \times 4x[/tex] [tex] \red \rightarrow1176 \times 2 = 3x \times 4x[/tex] [tex] \red \rightarrow2352 = 12 {x}^{2} [/tex] [tex] \red \rightarrow \frac{ \cancel{2352}}{ \cancel{12}} = {x}^{2} [/tex] [tex] \red \rightarrow196 = {x}^{2} [/tex] [tex] \red \rightarrow \sqrt{196} = \sqrt{ {x}^{2} } [/tex] [tex] \red \rightarrow14 = x[/tex] ᴀʟᴛɪᴛᴜᴅᴇ = 4x => 4x => 4 (14) =>56 ᴏᴘᴛɪᴏɴ ɴᴏ.4 (56 ᴄᴍ) ɪꜱ ᴄᴏʀʀᴇᴄᴛ. ──────────────────────────── Reply
Answer:
Given :–
Area of triangle = 1176 cm²
Ratio of base to altitude = 3:4
To Find :–
Altitude
Solution :–
Let the base be 3x and altitude be 4x
[tex] \sf \: 1176 = \dfrac{1}{2} \times 3x \times 4x[/tex]
[tex] \sf \: 1176 \times 2 = 3x \times 4x[/tex]
[tex] \sf \: 2352 = 12 {x}^{2} [/tex]
[tex] \sf \dfrac{2352}{12} = {x}^{2} [/tex]
[tex] \sf \:196 = {x}^{2} [/tex]
[tex] \sf \: \sqrt{196} = \sqrt{ {x}^{2} } [/tex]
[tex] \sf \: 14 = x[/tex]
Altitude = 4x
[tex] \sf \: 4 x[/tex]
[tex] \sf \: 4(14)[/tex]
[tex] \sf \: 56[/tex]
Option 4
[tex] \huge { \blue { \fbox{ \red{Qᴜᴇꜱᴛɪᴏɴ}}}}[/tex]
If the area of a triangle is 1176 cm² and base : corresponding altitude is 3:4, then the altitude
of the triangle is:
1) 42 cm
2) 52 cm
3) 54 cm
4) 56cm
[tex] \huge { \blue{\fbox{ \red{ᴀnswer}}}}[/tex]
ɢɪᴠᴇɴ:
ᴛᴏ ꜰɪɴᴅ:
ꜱᴏʟᴜᴛɪᴏɴ:
ʟᴇᴛ ᴛʜᴇ ʙᴀꜱᴇ ʙᴇ ‘3x’ ᴀɴᴅ ᴀʟᴛɪᴛᴜᴅᴇ ʙᴇ ‘4x’
[tex] \red\rightarrow1176 = \frac{1}{2} \times 3x \times 4x[/tex]
[tex] \red \rightarrow1176 \times 2 = 3x \times 4x[/tex]
[tex] \red \rightarrow2352 = 12 {x}^{2} [/tex]
[tex] \red \rightarrow \frac{ \cancel{2352}}{ \cancel{12}} = {x}^{2} [/tex]
[tex] \red \rightarrow196 = {x}^{2} [/tex]
[tex] \red \rightarrow \sqrt{196} = \sqrt{ {x}^{2} } [/tex]
[tex] \red \rightarrow14 = x[/tex]
ᴀʟᴛɪᴛᴜᴅᴇ = 4x
=> 4x
=> 4 (14)
=>56
ᴏᴘᴛɪᴏɴ ɴᴏ.4 (56 ᴄᴍ) ɪꜱ ᴄᴏʀʀᴇᴄᴛ.
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