If the area of a sectangular land is (a²-b²) sg. units
whose
breadth is (a-b) then, its length
is
​

2 thoughts on “If the area of a sectangular land is (a²-b²) sg. units<br /> whose<br />breadth is (a-b) then, its length<br />is<br />​”

1. i think it is rectangle

   Let l , w be the length , width/breadth of the rectangle respectively.

   then,

   ar(rect) = l*w = a^2 – b^2 ———(1)

   now , w = (a-b) ——–(2)

   substituting the value of 2 in 1 , we get

   _____answered by advik190____

   L * ( a-b) = (a^2-b^2)

   l = (a^2 – b^2) / (a-b) [using identity x^2 – y^2 = (x-y)(x+y)]

   l = (a-b) (a+b) / (a-b)

   l = a+b

   Reply

2. ❥A᭄ɴsᴡᴇʀ࿐

   given,

   • area=a²–b²

   • breadth=(a–b)

   • To find :– length of rectangle

   • let length is l units

   area of rectangle =length×breadth

   a²–b²={a–b}×l ––––––––––(1)

   • using identity a²–b²=(a+b) (a–b)

   • substituting value of a²–b² in equation (1)

   • (a+b) (a–b)= (a–b)×l

   • l=(a+b) unit

   length of rectangle is (a+b) unit.

   Reply