If [tex] \frac{ {2}^{x}}{ {2}^{x} + 1} = 3[/tex], then find the value of

[tex] \frac{ {8}^{x}}{ {8}^{x} + 1} [/tex]​

1 thought on “If [tex] \frac{ {2}^{x}}{ {2}^{x} + 1} = 3[/tex], then find the value of <br /><br />[tex] \frac{ {8}^{x}}{ {8}^{x} + 1} [/tex]​”

1. Step-by-step explanation:

   multiply both side by 4

   then{8}^{x}}{ {8}^{x} + 4} will be formed

   and could be written as {8}^{x}}{ {8}^{x} + 3+1}

   therefore{ {8}^{x}}{ {8}^{x} + 1} will be 12-3

   =9

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