If tan a + cot a = m. then : tan⁴a + cot⁴a =
(a) m-4m²2
(b) m + 4m? – 2
lem-4m2 – 2 (d) 44m2 + 2​

1 thought on “If tan a + cot a = m. then : tan⁴a + cot⁴a =<br />(a) m-4m²2<br />(b) m + 4m? – 2<br />lem-4m2 – 2 (d) 44m2 + 2​”

1. Solution:

   Solution:

   Given Equation in tan A+cotA=4.

   On squating both sides, we get =tan^2A+cit^2A+2tanAcotA=16

   ,=tan^2A+cot^2A+2*tanA(1/tanA) =16

   tan ^2A+cot^2A+2=16

   tan^2A+cit^=16-2

   tan^2A+cot^2A=14.

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