If sino = nsin (thita+2 a) then tan (thita + a)
is equal to​

1 thought on “If sino = nsin (thita+2 a) then tan (thita + a)<br />is equal to​”

1. Answer:

   Correct option is

   A

   1−n

   1+n

   tanα

   sinθ=nsin(θ+2α)

   sin(θ+2α)

   sinθ

   =n

   apply componendo dividendo rule,

   sinθ−sin(θ+2α)

   sinθ+sin(θ+2α)

   =

   n−1

   n+1

   apply sinC+sinD and sinC−sinD

   2sinαcos(θ+α)

   2sin(θ+α)cosα

   =

   n−1

   n+1

   tanα

   tan(θ+α)

   =

   n−1

   n+1

   tan(θ+α)=

   n−1

   n+1

   tanα

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