If Sin(A+B) =V3/2=Cos (A-B),
0°<A+B<90° (A>B),
Find the value of A and B.​

1 thought on “If Sin(A+B) =V3/2=Cos (A-B),<br />0°<A+B<90° (A>B),<br />Find the value of A and B.​”

1. [tex]\bold\red{\fbox{\sf{Solution}}}[/tex]

   sin(A+B)=cos(A-B)=√3/2

   ∴, sin(A+B)=√3/2

   or, sin(A+B)=sin60°

   or, A+B=60° –(1)

   cos(A-B)=√3/2

   or, cos(A-B)=cos30°

   or, A-B=30° –(2)

   Adding (1) and (2) we get,

   2A=90°

   or, A=45°

   Putting in (1) we get,

   45°+B=60°

   or, B=15°

   ∴, A=45°, B=15°

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