If sin 0 + cos = root 2, find value of sin -cos .

plss fassssstttttttt​

2 thoughts on “If sin 0 + cos = root 2, find value of sin -cos .<br /><br />plss fassssstttttttt​”

1. Answer:

   [tex][/tex]

   • Force is push or pull acting on a body which tends to change its state of rest or of motion.
   • It is denoted by “F”.

   Reply

2. Answer:

   0

   Step-by-step explanation:

   By squaring we get,

   [tex] {( \sin(x) + \cos(x)) }^{2} = { \sqrt{2} }^{2} [/tex]

   [tex] { \sin(x) }^{2} + 2 \sin(x) \cos(x) + { \cos(x) }^{2} = 2[/tex]

   [tex]1 + 2 \sin(x) \cos(x) = 2[/tex]

   [tex] \sin(x) \cos(x) = \frac{1}{2} [/tex]

   Now,

   [tex] {( \sin(x) – \cos(x)) }^{2} = { \sin(x) }^{2} – 2 \sin(x) \cos(x) + { \cos(x) }^{2} [/tex]

   [tex] { (\sin(x) – \cos(x) ) }^{2} = 1 – 2 \times \frac{1}{2} = 0[/tex]

   so,

   [tex] \sin(x) – \cos(x) = 0[/tex]

   Reply