Answer: If p and q are roots of x²+px-q=0 Then, we know α+β = -b/a and αβ= c/a p+q = -p/1 and pq = q/1 q = -2p and p=1 Putting p=1 in q=-2p q=-2 Hence p=1 and q=-2 Reply
Answer:
If p and q are roots of x²+px-q=0
Then, we know α+β = -b/a
and αβ= c/a
p+q = -p/1 and pq = q/1
q = -2p and p=1
Putting p=1 in q=-2p
q=-2
Hence p=1 and q=-2