if p and q are the zeros of the quadratic polynomial p(x)= 4x^2-5x-1, find the value of p^2q+pq^2 About the author Serenity
Step-by-step explanation: Given :– p and q are the zeros of the quadratic polynomial p(x)= 4x^2-5x-1 To find :– Find the value of p^2q+pq^2 ? Solution :– Given quardratic polynomial P(x)=4x^2-5x-1 On Comparing this with the standard quadratic Polynomial ax^2+bx+c We have a = 4 b = -5 c = -1 Given that p and q are the zeores of P(x) We know that The sum of the zeroes = -b/a =>p+q = -(-5)/4 => p+q = 5/4 ——-(1) and The product of the zeroes = c/a => p×q = -1/4 => pq = -1/4 ——–(2) Now p^2q + pq^2 => pq(p+q) From (1)&(2) then => (-1/4)(5/4) => (-1×5)/(4×4) => -5/16 Answer:– The value of p^2q + pq^2 for the given problem is –5/16 Used formulae:– The standard quadratic Polynomial is ax^2+bx+c. Sum of the zeores = -b/a The product of the zeroes = c/a Reply
Step-by-step explanation:
Given :–
p and q are the zeros of the quadratic polynomial p(x)= 4x^2-5x-1
To find :–
Find the value of p^2q+pq^2 ?
Solution :–
Given quardratic polynomial P(x)=4x^2-5x-1
On Comparing this with the standard quadratic Polynomial ax^2+bx+c
We have
a = 4
b = -5
c = -1
Given that
p and q are the zeores of P(x)
We know that
The sum of the zeroes = -b/a
=>p+q = -(-5)/4
=> p+q = 5/4 ——-(1)
and
The product of the zeroes = c/a
=> p×q = -1/4
=> pq = -1/4 ——–(2)
Now
p^2q + pq^2
=> pq(p+q)
From (1)&(2) then
=> (-1/4)(5/4)
=> (-1×5)/(4×4)
=> -5/16
Answer:–
The value of p^2q + pq^2 for the given problem is –5/16
Used formulae:–
Answer:
sorry bro I don’t know
you are in which class