if p=2+√5 / 2-√5 and q=2-√5 / 2+√5 , find the values of. (1) p+q (ii) p-q (ii) p²+q²(IV) p²-q About the author Bella
Answer: p=2+√5/2-√5 =(2+√5)(2+√5)/(2-√5)(2+√5) =(2+√5)^2/(2^2-√5^2) =(2+√5)^2/4-5 = -(2+√5)^2 q=2-√5/2+√5 =(2-√5)(2-√5)/(2+√5)(2-√5) =(2-√5)^2/4-5 = -(2-√5)^2 I) p+q = -(2+√5)^2-(2-√5)^2 = -(4+5+4√5)-(4+5-4√5) =-9-4√5-9+4√5 = -18 ii) p-q = -(2+√5)^2+(2-√5)^2 = -(4+5+4√5)+(4+5-4√5) = -9-4√5+9-4√5 = -8√5 Reply
Answer:
p=2+√5/2-√5
=(2+√5)(2+√5)/(2-√5)(2+√5)
=(2+√5)^2/(2^2-√5^2)
=(2+√5)^2/4-5
= -(2+√5)^2
q=2-√5/2+√5
=(2-√5)(2-√5)/(2+√5)(2-√5)
=(2-√5)^2/4-5
= -(2-√5)^2
I) p+q
= -(2+√5)^2-(2-√5)^2
= -(4+5+4√5)-(4+5-4√5)
=-9-4√5-9+4√5
= -18
ii) p-q
= -(2+√5)^2+(2-√5)^2
= -(4+5+4√5)+(4+5-4√5)
= -9-4√5+9-4√5
= -8√5