if one root of the quadratic equation (x+4) (x+3)=0 is -4, then the other root is​

2 thoughts on “if one root of the quadratic equation (x+4) (x+3)=0 is -4, then the other root is​”

1. [tex]\huge\bf\pink{รσℓµƭเσɳ}[/tex]

   ✔︎ (x+4)(x+3) = 0

   ✔︎ (x+4) = 0 & (x+3) = 0

   ✔︎[tex]\sf\pink{ x=-4 \:and\: x=-3}[/tex]

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2. if one root of the quadratic equation (x+4) (x+3)=0 is -4, then the other root is

   AnSweR:–

   • The Other Root is [tex]\Large{\red{\bold{-3}}}[/tex]

   → (x+4)(x+3) = 0

   → (x+4) = 0 & (x+3) = 0

   → x = -4 & x = –3

   [tex]\Large{✓}[/tex]

   Hope It Helps You ✌️

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