Step-by-step explanation: 2n x 5m 2n is always even for all values of n. 5m is always odd and ends with 5 for all values of m. But 2n x 5m is always even and ends in 0. ∴ 2n x 5m cannot end with the digit 5 for any values of m. No value of m will satisfy 2n x 5m ends in 5. Reply
Step-by-step explanation:
2n x 5m
2n is always even for all values of n.
5m is always odd and ends with 5 for all values of m. But 2n x 5m is always even and ends in 0.
∴ 2n x 5m cannot end with the digit 5 for any values of m. No value of m will satisfy 2n x 5m ends in 5.