if x€[0, 5] , then what is the probability that:::[tex]x^2-3x+2>0[/tex]​

1 thought on “if x€[0, 5] , then what is the probability that:::[tex]x^2-3x+2>0[/tex]​”

1. Step-by-step explanation:

   `x^2-3x+2 ge 0`

   `=>(x-1)(x-2) ge 0`

   It means, `x ge 2` and `x le 1`

   If we draw it on the number line, from points `0` to `5`, we can see that `4/5` of the part is covered. So, the required probability is `4/5`.

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