Answer: Step by step explanation:- Given: x²-kx-6= (x-6)(x+1) To find: we have to find the value of x x²-kx-6= (x-6)(x+1) Firstly expanding the terms and opening the brackets on the LHS => x²-kx-6= x( x+1)-6(x+1) => x²-kx-6= x²+x-6x-6 => x²-kx-6= x²-5x-6 Both sides quadratic equation is formed . Both side LHS and RHS which are same cancel it, x² and x and -6 become cancel after comparing,we get -k= -5 than minus minus both side cancel k= 5 Check x²-kx-6 =>x²-5x-6 which is equal to the RHS Reply
Given x²-kx-6= (x-6)(x+1) To find we have to find the value of x [tex]\sf\huge {\underline{\underline{{Solution}}}}[/tex] x²-kx-6= (x-6)(x+1) Firstly expanding the terms and opening the brackets on the LHS => x²-kx-6= x( x+1)-6(x+1) => x²-kx-6= x²+x-6x-6 => x²-kx-6= x²-5x-6 we see on both sides quadratic equation is formed . Now , comparing the coefficient of x on both sides because we have to find the value of x and on the right side k is the coefficient of x. after comparing,we get -k= -5 k= 5 Check x²-kx-6 =>x²-5x-6 which is equal to the RHS Reply
Answer:
Step by step explanation:-
Given:
x²-kx-6= (x-6)(x+1)
To find:
we have to find the value of x
x²-kx-6= (x-6)(x+1)
Firstly expanding the terms and opening the brackets on the LHS
=> x²-kx-6= x( x+1)-6(x+1)
=> x²-kx-6= x²+x-6x-6
=> x²-kx-6= x²-5x-6
Both sides quadratic equation is formed .
Both side LHS and RHS which are same cancel it,
x² and x and -6 become cancel
after comparing,we get -k= -5
than minus minus both side cancel
k= 5
Check
x²-kx-6
=>x²-5x-6 which is equal to the RHS
Given
x²-kx-6= (x-6)(x+1)
To find
we have to find the value of x
[tex]\sf\huge {\underline{\underline{{Solution}}}}[/tex]
x²-kx-6= (x-6)(x+1)
Firstly expanding the terms and opening the brackets on the LHS
=> x²-kx-6= x( x+1)-6(x+1)
=> x²-kx-6= x²+x-6x-6
=> x²-kx-6= x²-5x-6
we see on both sides quadratic equation is formed .
Now , comparing the coefficient of x on both sides because we have to find the value of x and on the right side k is the coefficient of x.
after comparing,we get -k= -5
k= 5
Check
x²-kx-6
=>x²-5x-6 which is equal to the RHS