if f(x) ={x2-x-6/x2-2x-3}x=3,

find k so that the function f may be continuous at x = 3.​

1 thought on “if f(x) ={x2-x-6/x2-2x-3}x=3,<br /><br />find k so that the function f may be continuous at x = 3.​”

1. Answer:

   [tex] \frac{ {x}^{2} – x – 6}{ {x}^{2} – 2x – 3 } \\ = \frac{ {x}^{2} – 3x + 2x – 6 }{ {x}^{2} – 3x + x – 3 } \\ = \frac{x(x – 3) + 2(x – 3)}{x(x – 3) + 1(x – 3)} \\ = \frac{( \cancel{ x – 3})(x + 2)}{( \cancel{ x – 3})(x + 1)} \\ = \frac{x + 2}{x + 1} [/tex]

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