Answer: we usually know cot tetha=adjacent side/opposite side so hypotenus=sqr root(40^2+9^2)=41 cosec tetha =hypotenus/opposite=41/9 sin tetha= 1/cosec tetha = 9/41 Reply
Answer:
we usually know cot tetha=adjacent side/opposite side
so hypotenus=sqr root(40^2+9^2)=41
cosec tetha =hypotenus/opposite=41/9
sin tetha= 1/cosec tetha = 9/41
Answer:
cos theta = 1/ sec theta
sin theta = 1/ cosec theta