if c=a/b-d-e/f-d,find the value of f when a=3,b=4 c=-6,d=-5,e=2​

1 thought on “if c=a/b-d-e/f-d,find the value of f when a=3,b=4 c=-6,d=-5,e=2​”

1. Step-by-step explanation:

   f={8/67} (decimal: .119403 to 6d. p)

   PREMISES

   The cardinal value of “f” in the equation c=a/b-d-e/f-d, where a=3, b=4 c=-6, d=-5, and e=2

   CALCULATIONS

   For the equation c=a/b-d-e/f-d, the cardinal value of the independent variable “f” can be calculated by deduction, where a=3, b=4, c=-6, d=-5, and e=2

   Hence,

   The mathematical proposition c=a/b-d-e/f-d becomes

   -6=3/4-(-5)-2/f-(-5)

   -6=3/4+5–2/f+5

   -6–5–5=3/4+(5–5)-2/f+(5–5)

   -16=3/4+0–2/f+0

   -16=3/4–2/f

   -16–3/4=(3/4–3/4)-2/f

   (-16 3/4)=0–2/f

   (-16 3/4)=-2/f (Eliminate the fractions by multiplying both sides of the equation by the least common denominator 4×f=4f)

   4f[(-16 3/4)=-2/f]

   4f[-67/4=-2/f]

   -67f=-8

   -67f/-67=-8/-67

   f=

   8/67 as a proper fraction (decimal: .119403 to 6d. p)

   PROOF

   If f=8/67, then the equations

   c=3/4-(-5)-2/f-(-5)

   -6=3/4+5–2/(8/67)+5

   -6=(3/4+5+5)-2(67/8)

   -6=(10 3/4)-2(67/8)

   -6=43/4–67/4

   -6=(43–67)/4

   -6=-24/4 and

   -6=-6 establish the root (zero) f=8/67 of the mathematical proposition -6=3/4-(-5)-2/f-(-5)

   C.H.

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