if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​

2 thoughts on “if area of rombus is 100cm2 and one of its diagnol is twice of other them find the value of bigger diagonal​”

1. Step-by-step explanation:

   let first diagnol=x

   second diagnol=2x

   x×2x=200

   then x^2=100

   x=10

   bigger diagnol=10×2=20

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2. [tex]\small{\textsf{\textbf{\underline{\underline{The value of bigger diagonal is 20 cm. \::}}}}} \\ [/tex]

   Step-by-step explanation:

   Given that:

   • Area of a rhombus is 100 cm².
   • One of its diagnol is twice of other.

   To Find:

   • The value of bigger diagonal.

   Let us assume:

   • Smaller diagonal of a rhombus be x.
   • Bigger diagonal = 2x

   Formula used:

   Area of a rhombus = (P × Q)/2

   Where,

   • P = Bigger diagonal of a rhombus
   • Q = Smaller diagonal of a rhombus

   Finding the value of bigger diagonal:

   According to the question.

   ⟶ (P × Q)/2 = 100

   ⟶ (2x × x)/2 = 100

   ⟶ 2x²/2 = 100

   ⟶ x² = 100

   ⟶ x = √100

   ⟶ x = 10

   [tex]\small{\textsf{\textbf{\underline{\underline{∴ The value of bigger diagonal = 2x = (2 × 10) = 20 cm\::}}}}} \\ [/tex]

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