if alpha and beta are the zeros of the polynomials x²-5x+6 find a polynomial whose zeros are (i)alpha/beta and beta/alpha (ii)alpha+1/alpha-1 and beta+1/beta-1 About the author Eva
x2-5x+6 x2-2x-3x+6=0 x(x-2)-3(x-2)=0 (x-2)(x-3)=0 x=2,x=3 therefore zeroes of polynomial of x2-5x+6 are 2,3 alpha =2and beta3 sum of zeroes alpha +beta =-b/a 2+3=-(-5)/1 5=5 product of zeroes are aplha×beta =c/a 2×3=6 6=6 Reply
x2-5x+6
x2-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0
x=2,x=3
therefore zeroes of polynomial of x2-5x+6 are 2,3
alpha =2and beta3
sum of zeroes alpha +beta =-b/a
2+3=-(-5)/1
5=5
product of zeroes are aplha×beta =c/a
2×3=6
6=6