If a number x is chosen at random from the numbers -2 , -1 , 0 , 1 , 2.What is the
probability that x2  2.

1 thought on “If a number x is chosen at random from the numbers -2 , -1 , 0 , 1 , 2.What is the<br />probability that x2  2.<br /><br /><br />”

1. Answer:

   Total possible outcomes = 5 {-2,-1,0,1,2}

   Favourable outcomes = 3 {-1,0,1}(x^2<2)

   If X is -2 , then x^2 = 4 which is greater than 2. (-2)^2>2= 4>2. So X can’t be-2.

   Similarly, X can’t be 2.

   But it can be -1,0 or 1.

   So , P(E) = 3/5.

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