If 4 root of the equaction x
[tex]x ^{2} + ax – 8 = 0[/tex]
then a=
​

2 thoughts on “<br />If 4 root of the equaction x<br />[tex]x ^{2} + ax – 8 = 0[/tex]<br />then a=<br />​”

1. Given:–

   • Quadratic Equation → x²+ax-8 = 0
   • Root of the equation = 4

   To Find:–

   • Value of a

   Solution:–

   Value of x = 4

   Substitute x = 4 in the Q.E

   → (4)²+a4-8 = 0

   → 16+a4-8 = 0

   → 16+a4 = 8

   → a4 = 8-16

   → a = -8/4

   → a = -2

   ∴ Value of a = –2.

   [tex]\Large{✓}[/tex]

   Hope It Helps You ✌️

   Reply

2. a = -2

   Step-by-step explanation:

   According to the question, we are given a quadratic equation:

   x² + ax -8 = 0

   We are also given one root of the equation: 4.

   We need to find the value of a.

   Since one of its roots is 4, this implies that x = 4. Our job is to substitute the value of 4 in the given quadratic equation.

   → x² + ax – 8 = 0

   → (4)² + 4a – 8 = 0 [x = 4]

   → 16 + 4a – 8 = 0

   → 8 + 4a = 0

   → 4(2 + a) = 0

   → 2 + a = 0

   → a = -2

   Finally, we have got our value of a as -2.

   # Learn More:

   1. X^2-4x+3=0 answer me fast​

   brainly.in/question/39697488

   2. Find the product of the roots of quadratic equation 2x² +7x -4 = 0

   brainly.in/question/39688497

   Reply