2 thoughts on “if (-4,0) and (4,0) are two vertices of an equilateral triangle find the vertex of its third vertex”
Answer:
(0, 4[tex]\sqrt{3\\}[/tex]) or (0, -4[tex]\sqrt{3\\}[/tex])
Step-by-step explanation:
See so the length of one side is 8 and its equilateral traingle so all sides are equal. If you look carefully thr midpoint of given vertices is origin and since the perpendicular bisector of equilateral triangle passes through mid point of the side it is safe assume that it touches origin i.e. (0,0)
So.. this is now a game to find a side in a right angled traingle –> one side is of length 4 and hypotenuse is of length 8 and now we need to find the other side by pythegorous theorem
let A(x,y) is the coordinate of the third point. We are given B(-4,0) and C(4,0). As given triangle is an equilateral triangle. So, coordinates of third vertex will be A(0,4√3).
Answer:
(0, 4[tex]\sqrt{3\\}[/tex]) or (0, -4[tex]\sqrt{3\\}[/tex])
Step-by-step explanation:
See so the length of one side is 8 and its equilateral traingle so all sides are equal. If you look carefully thr midpoint of given vertices is origin and since the perpendicular bisector of equilateral triangle passes through mid point of the side it is safe assume that it touches origin i.e. (0,0)
So.. this is now a game to find a side in a right angled traingle –> one side is of length 4 and hypotenuse is of length 8 and now we need to find the other side by pythegorous theorem
Answer:
let A(x,y) is the coordinate of the third point. We are given B(-4,0) and C(4,0). As given triangle is an equilateral triangle. So, coordinates of third vertex will be A(0,4√3).