If x=2x^2-3xy+4y y=x^2+2xy-3y^2 z=-4x^2+5xy+y^2 Find x+y+z
Answer:
(2x 2-3xy+4y)+(x2+2xy-3y2)+(4×2+5xy+2y)
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Answer:
(2x 2-3xy+4y)+(x2+2xy-3y2)+(4×2+5xy+2y)