If 15.0 liters of neon at 25.0 °C is allowed to expand to 45.0 liters, what must the new temperature be to maintain constant press

Given:–

• Volume of Neon ,V₁ = 15 l
• Temperature ,T₁ = 25°C = 25×274.15° = 298.15
• Volume ,V₂ = 45 l

To Find:–

New temperature to maintain constant pressure ,T₂

Solution:–

⠀⠀⠀⠀⠀According to the Given Condition

It is given that the volume of neon (initial) 15 litres at 25°C is allowed to expand to 45 liters . We have to calculate the new temperature to be maintain constant pressure .

Using Charles Law

[tex]:\implies[/tex] V₁/T₁ = V₂/T₂

Substitute the value we get

[tex]:\implies[/tex] 15/298.15= 45/T₂

[tex]:\implies[/tex] 15/298.15 = 45/T₂

[tex]:\implies[/tex] T₂ = 45×298.15/15

[tex]:\implies[/tex] T₂ = 3×298.15

[tex]:\implies[/tex] T₂ = 894.45 K

Hence, the required temperature to maintain the constant pressure is 894.45 Kelvin.

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