If 1 is a zero of the polynomial p(x) = ax² – 3(a – 1) x – 1, then find the value of a

2 thoughts on “If 1 is a zero of the polynomial p(x) = ax² – 3(a – 1) x – 1, then find the value of a”

1. Answer:

   Now, we divide p ( x ) = a x 2 – 3 ( a – 1 ) x – 1 by x − 1. Hence, the value of a is 1

   Step-by-step explanation:

   Given: p(x)=ax

   2

   −3(a−1)x−1

   One of the zero =1

   As one of the zeroes is 1, substituting it in the polynomial

   ⇒p(1)=0=a−3(a−1)−1

   ⇒0=−2a+3−1

   ⇒a=1

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2. Answer:

   a=1

   Step-by-step explanation:

   p(1)=a(1)2 – 3×(a-1)×1 – 1=0

   a-3a+3-1=0

   -2a+2=0

   -2a=-2

   a=2/2=1

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