i) The sum of the digits of a two-digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number.
1 thought on “i) The sum of the digits of a two-digit number is 9. Also, nine times this number is<br />twice the number obtained by reversing t”
ANSWER:–
Let the ten’s digit no. be x and one’s digit no. be y.
So the no. will be = 10x+y.
Given : x+y=9—–(I)
9(10x+y)=2(10y+x) ⇒88x−11y=0 —–(II)
On solving I and II simultaneously you will get x=1 and y=8.
Therefore your desired no. is 18
ADDITIONALINFORMATION:–
HOW TOREVERSEA NUMBER?
The modulo operator (%) returns the remainder of a divison. In this case, we divide number by 10 and return the remainder. Consider the integer 1234. … The remainder of the division will be 4 representing the ones column which could not be divided by 10.
ANSWER:–
Let the ten’s digit no. be x and one’s digit no. be y.
So the no. will be = 10x+y.
Given : x+y=9—–(I)
9(10x+y)=2(10y+x) ⇒88x−11y=0 —–(II)
On solving I and II simultaneously you will get x=1 and y=8.
Therefore your desired no. is 18
ADDITIONAL INFORMATION:–
The modulo operator (%) returns the remainder of a divison. In this case, we divide number by 10 and return the remainder. Consider the integer 1234. … The remainder of the division will be 4 representing the ones column which could not be divided by 10.