(i) 12, 15, 20, 27 (ii) 22, 54, 108, 135, 198.
36. Find the smallest number which leaves remainders 8 and 12 when divided by

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(i) 12, 15, 20, 27 (ii) 22, 54, 108, 135, 198.
36. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 2
respectively.
37. Find the largest number of three digits which is exactly divisible by 96 and 240​

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Remi

1 thought on “(i) 12, 15, 20, 27 (ii) 22, 54, 108, 135, 198.<br />36. Find the smallest number which leaves remainders 8 and 12 when divided by”

  1. Answer:

    36) 204

    37) 480.

    Step-by-step explanation:

    36) Divisors are 28 & 32, as required. Remainder are also the required number 8 & 12. Hence 204 is the required answer.

    37) Answer. LCM of 96 and 240 = 2*2*2*2*2*3*5 = 480.

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