how much is minus 6 x square + 7 y cube is greater than than to x square minus y cube​

how much is minus 6 x square + 7 y cube is greater than than to x square minus y cube​

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  1. Answer :

    [tex] – 6 {x}^{2} + 7 {y}^{3} \\ \: \: \: \: \: {x}^{2} – {y}^{3} \\ ( – ) \: ( – ) \\ – – – – – – \\ – 7 {y}^{2} + 8 {y}^{3} \\ – – – – – – \\ \\ – 6 {x}^{2} + 7 {y}^{3} \: \: is \: \: – 7 {y}^{2} + 8 {y}^{3} \: \: greater \\ than \: \: to \: \: {x}^{2} – {y}^{3}[/tex]

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