a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n =
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636=
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=0
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12 Hence, 12 terms of the A.P. is required to give a sum of 636.
Answer:
Your answer is here:-
Step-by-step explanation:
d = 17 -9 = 8 a= 9
sum = n/2 [ 2a + ( n-1 )d ]
636 = n/2 [ 2×9 + ( n-1 ) x 8 ]
636×2 = n [ 18 + ( n-1 ) x 8 ]
1272 = n [ 18 + 8n – 8 ]
1272 = n [ 8n + 18 – 8 ]
1272 = n [ 8n + 10 ]
1272 = 8n² + 10n
0 = 8n² + 10n – 1272
8n² + 10n – 1272 = 0
2( 4n² + 5n – 636 ) = 0
4n² + 5n – 636 = 0x 2
4n² + 5n – 636 = 0
Using splitting the middle term
4n² + 53n – 48n – 636
n( 4n + 53 ) – 12( 4n + 53 )
( n-12 ) ( 4n + 53 )
n= 12 or n = -53/ 4
the term can only be 12 but not -53/4 .
So the answer is 12th term.
Hope it helps you.
Answer:
a
a 1
a 1
a 1 =9
a 1 =9a
a 1 =9a 2
a 1 =9a 2
a 1 =9a 2 =a
a 1 =9a 2 =a 1
a 1 =9a 2 =a 1
a 1 =9a 2 =a 1 +d=17
a 1 =9a 2 =a 1 +d=179+d=17
a 1 =9a 2 =a 1 +d=179+d=17d=8
a 1 =9a 2 =a 1 +d=179+d=17d=8
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n =
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636=
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=0
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12
a 1 =9a 2 =a 1 +d=179+d=17d=8 We know that, the sum of n terms of an A.P. is,S n = 2n {2a+(n−1)d} According to the question,636= 2n {2(9)+(n−1)8}1272=18n+8n 2 −8n8n 2 +10n−1272=04n 2 +5n−636=0n=12,−13.25 Ignore the negative value.n=12 Hence, 12 terms of the A.P. is required to give a sum of 636.