We have to find the number of solutions of the equation ||2x – 3| – m| = m where m > 0. solution : here m > 0 , it means ||2x – 3| – m| is positive term. so, |2x – 3| – m = m ⇒|2x – 3| = 2m ⇒2x – 3 = ± 2m ⇒2x = 3 ± 2m ⇒x = (3 ± 2m)/2 also |2x – 3| = 0 ⇒2x = 3 ⇒x = 3/2 Therefore x = (3 + 2m)/2, (3 – 2m)/2 and 3/2 are the solutions of equation. so there are three solutions of the given equation. Reply
We have to find the number of solutions of the equation ||2x – 3| – m| = m where m > 0.
solution : here m > 0 , it means ||2x – 3| – m| is positive term.
so, |2x – 3| – m = m
⇒|2x – 3| = 2m
⇒2x – 3 = ± 2m
⇒2x = 3 ± 2m
⇒x = (3 ± 2m)/2
also |2x – 3| = 0 ⇒2x = 3 ⇒x = 3/2
Therefore x = (3 + 2m)/2, (3 – 2m)/2 and 3/2 are the solutions of equation.
so there are three solutions of the given equation.