How many of the following are Pythagorean triplets ?[8, 15, 17], [13, 60, 61], [14, 48, 50). [11, 40, 41).Explain it!!!! About the author Ava
Question :- To find which of the following are Pythagorean triplets. Answer :- Concept :- According to the Pythagorean triplet, the three numbers are in the form as follows :- 2m m² – 1 m² + 1 2m being the smallest number Option 1 :- ➵ 8,15,17 In this set, 8 is the smallest number. Therefore, → 2m = 8 → m = 8 ÷ 2 → m = 4 Now that we have the value of m, the other 2 numbers will be :- → m² – 1 → (4)² – 1 → 16 – 1 → 15 The third number :- → m² + 1 → (4)² + 1 → 16 + 1 → 17 All the answer’s are matching the set. Hence, 8,15,17 is a Pythagorean triplet. Option 2 :- ➵ 13,60,61 Here, the smallest number is 13. → 2m = 13 13 is not exactly divisible by 2. Hence this triplet cannot be formed. Option 3 :- ➵ 14,48,50 Here 14, is the smallest number. Therefore, → 2m = 14 → m = 14 ÷ 2 → m = 7 Second number :- → m² – 1 → (7)² – 1 → 49 – 1 → 48 Third number :- → m² + 1 → (7)² + 1 → 49 + 1 → 50 All the numbers are matching the set, hence 14,48,50 is a Pythagorean triplet Option 4 :- ➵ 11,40,41 → 2m = 11 Here 11 is not exactly divisible by 2. Hence the triplet cannot be formed. Reply
Question :-
To find which of the following are Pythagorean triplets.
Answer :-
Concept :-
According to the Pythagorean triplet, the three numbers are in the form as follows :-
2m being the smallest number
Option 1 :-
➵ 8,15,17
In this set, 8 is the smallest number.
Therefore,
→ 2m = 8
→ m = 8 ÷ 2
→ m = 4
Now that we have the value of m, the other 2 numbers will be :-
→ m² – 1
→ (4)² – 1
→ 16 – 1
→ 15
The third number :-
→ m² + 1
→ (4)² + 1
→ 16 + 1
→ 17
All the answer’s are matching the set. Hence, 8,15,17 is a Pythagorean triplet.
Option 2 :-
➵ 13,60,61
Here, the smallest number is 13.
→ 2m = 13
13 is not exactly divisible by 2. Hence this triplet cannot be formed.
Option 3 :-
➵ 14,48,50
Here 14, is the smallest number.
Therefore,
→ 2m = 14
→ m = 14 ÷ 2
→ m = 7
Second number :-
→ m² – 1
→ (7)² – 1
→ 49 – 1
→ 48
Third number :-
→ m² + 1
→ (7)² + 1
→ 49 + 1
→ 50
All the numbers are matching the set, hence 14,48,50 is a Pythagorean triplet
Option 4 :-
➵ 11,40,41
→ 2m = 11
Here 11 is not exactly divisible by 2. Hence the triplet cannot be formed.