How do find the standard equation of the circle with center (3,-5) and passes through (1,2)? About the author Abigail
Step-by-step explanation: (x−h)2+(y−k)2=r2. (x−(−3))2+(y−5)2=102. i.e., (x+3)2+(y−5)2=100. Therefore, the equation of the circle is (x+3)2+(y−5)2=100. Reply
Step-by-step explanation:
(x−h)2+(y−k)2=r2.
(x−(−3))2+(y−5)2=102.
i.e., (x+3)2+(y−5)2=100.
Therefore, the equation of the circle is (x+3)2+(y−5)2=100.