go Using Euclid’s algorithm, find the H.CF of:1152 116641) 1152, 1664HCF (1152 , 1664) = 128– 11929 12 15 2721664 = 1152 XL+ 512-10241152, 512 X 2 + 128128 5)24512= 128 X 3.to-912HCF = 128Oi 504, 1188 About the author Rose
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I don’t know
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